(begin{array}{c|c} x & 1 & 4 & p \ hline y & 0.5 & 1 & 2.5end{array}). The table below satisfies the relation y – k(sqrt{x}), where k is a positive constant. Find the value of P,
- A. 2
- B. 4
- C. 10
- D. 25
Correct Answer: Option D
Explanation
From y = (frac{1}{2} sqrt{x})
when y = 2.5 or (frac{5}{2}), x = P
(frac{5}{2} times frac{1}{2} sqrt{P})
(sqrt{P} = frac{10}{2} = 5)
P = 52
= 25