A chord of a circle subtends an angle of 120° at the centre of a circle of diameter (4sqrt{3} cm). Calculate the area of the major sector.
-
A.
32(pi) cm(^2) -
B.
4(pi) cm(^2) -
C.
8(pi) cm(^2) -
D.
16(pi) cm(^2)
Correct Answer: Option C
Explanation
Angle of major sector = 360° – 120° = 240°
Area of major sector : (frac{theta}{360} times pi r^{2})
r = (frac{4sqrt{3}}{2} = 2sqrt{3} cm)
Area : (frac{240}{360} times pi times (2sqrt{3})^{2})
= (8pi cm^{2})
There is an explanation video available below.