A box contains two red balls and four blue balls. A ball is drawn at random from the box and then replaced before a second ball is drawn. Find the probability of drawing two red balls.
-
A.
(frac{2}{3}) -
B.
(frac{1}{3}) -
C.
(frac{1}{4}) -
D.
(frac{1}{9})
Correct Answer: Option D
Explanation
Total number of balls = 2 + 4 = 6
P(of picking a red ball) = (frac{2}{6}) = (frac{1}{3})
P(of picking a blue ball) = (frac{4}{6}) = (frac{2}{3})
With replacement,
P( picking two red balls) = (frac{1}{3}) × (frac{1}{3}) = (frac{1}{9})
There is an explanation video available below.