Class Interval |
Frequency |
60 – 64 | 2 |
65 – 69 | 3 |
70 – 74 | 6 |
75 – 79 | 11 |
80 – 84 | 8 |
85 – 89 | 7 |
90 – 94 | 2 |
95 – 99 | 1 |
The table shows the distribution of marks scored by students in an examination. Calculate, correct to 2 decimal places, the
(a) mean ; (b) standard deviation of the distribution.
Explanation
Class Interval |
Freq (f) |
Mid-point (x) |
(fx) | (x^{2}) | (fx^{2}) |
60 – 64 | 2 | 62 | 124 | 3844 | 7688 |
65 – 69 | 3 | 67 | 201 | 4489 | 13487 |
70 – 74 | 6 | 72 | 432 | 5184 | 31104 |
75 – 79 | 11 | 77 | 847 | 5929 | 65219 |
80 – 84 | 8 | 82 | 656 | 6724 | 53792 |
85 – 89 | 7 | 87 | 609 | 7569 | 52983 |
90 – 94 | 2 | 92 | 184 | 8464 | 16928 |
95 – 99 | 1 | 97 | 97 | 9409 | 9409 |
(sum) | 40 | 3150 | 250590 |
(a) Mean (bar{x} = frac{sum fx}{sum f})
= (frac{3150}{40})
= 78.75
(b) (SD = sqrt{frac{sum fx^{2}}{sum f} – (frac{sum fx}{sum f})^{2}})
= (sqrt{frac{250590}{40} – (frac{3150}{40})^{2}})
= (sqrt{6264.75 – (78.75)^{2}})
= (sqrt{6264.75 – 6201.5625})
= (sqrt{63.1875})
= 7.95.