(a) A dealer sold a car to a man and made a profit of 15%. The man then sold it to a woman for N120,175.00 at a loss of 5%. How much did the dealer buy the car?
(b) The diameter of the wheel of a car is 36cm. How many revolutions, correct to three significant figures, will it make to cover a distance of 1.05 km? [Take (pi = frac{22}{7})].
Explanation
(a) Let the cost of the car to the dealer be x.
Sales of car to a man with 15% profit : (115% of x = 1.15 x)
Sale of the car to the woman by the man at 5% loss : (95% of 1.15x = N120,175.00)
(0.95 times 1.15x = N120,175.00)
(1.0925x = N120,175.00)
(x = frac{120,175.00}{1.0925})
(x = N110,000)
The original cost of the car to the dealer = N110,000.00.
(b) Circumference of a circle = (2pi r)
Distance covered by the wheel = 1.05 km
Radius of the wheel = 18cm
Circumference of the wheel = (2 times frac{22}{7} times 18)
= (113.14 cm)
Note : 1.05 km = 105,000 cm
Number of revolution = (frac{105,000}{113.14})
= (928.05 revs)
(approxeq 928 revs)