When sickle cell carrier marries a normal woman, the probability of them having a normal offspring is
-
A.
0.75 -
B.
0.25 -
C.
0.5 -
D.
.1
Correct Answer: Option C
Explanation
A sickle cell carrier (AS) and a normal woman (AA), when crossed will yield:
2 normal offsprings (AA) and 2 sickle cell carrier (AS).
Hence, the probability of a normal child = (frac{2}{4})
= (0.5)
There is an explanation video available below.